The correct order of reactivity of (I) Anilin | vedclass

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Question

(A) The reactivity of an aromatic ring towards electrophilic substitution depends on the electron density on the ring.Aniline ($-NH_2$ group) is a str

Vedclass · Accepted Answer

$I > II > III$

Vedclass · Answer

(A) The reactivity of an aromatic ring towards electrophilic substitution depends on the electron density on the ring.Aniline ($-NH_2$ group) is a strong electron-donating group due to its $+M$ effect,which increases the electron density on the benzene ring,making it highly reactive.Benzene has no substituent,so it has moderate reactivity.Nitrobenzene ($-NO_2$ group) is a strong electron-withdrawing group due to its $-M$ and $-I$ effects,which significantly decrease the electron density on the benzene ring,making it the least reactive.Therefore,the order of reactivity is $Aniline (I) > Benzene (II) > Nitrobenzene (III)$.

The correct order of reactivity of $(I)$ Aniline,$(II)$ Benzene,and $(III)$ Nitrobenzene towards electrophilic substitution reaction is .....

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