The number of monobromo isomers of neopentane | vedclass

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(A) Neopentane is $2,2$-dimethylpropane,which has the structure $C(CH_3)_4$.All $12$ hydrogen atoms in neopentane are equivalent because the molecule

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$1$

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(A) Neopentane is $2,2$-dimethylpropane,which has the structure $C(CH_3)_4$.All $12$ hydrogen atoms in neopentane are equivalent because the molecule has a highly symmetrical tetrahedral structure.Replacing any one of these $12$ hydrogen atoms with a bromine atom results in the same product,$1$-bromo-$2,2$-dimethylpropane.Therefore,there is only $1$ possible monobromo isomer for neopentane.

The number of monobromo isomers of neopentane is ........ .

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