What is the number of optical isomers for 2, | vedclass

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(D) The structure of $2, 3-$dibromobutanoic acid is $CH_3-CH(Br)-CH(Br)-COOH$.This molecule contains two chiral centers at $C_2$ and $C_3$.The number

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$4$

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(D) The structure of $2, 3-$dibromobutanoic acid is $CH_3-CH(Br)-CH(Br)-COOH$.This molecule contains two chiral centers at $C_2$ and $C_3$.The number of stereoisomers is given by $2^n$,where $n$ is the number of chiral centers.Here,$n = 2$,so the total number of stereoisomers is $2^2 = 4$.These four stereoisomers consist of two pairs of enantiomers,which are optically active.Therefore,the number of optical isomers is $4$.

$(I)$ Optical Activity	$(II)$ Form	$(III)$ Sign	$(IV)$ Rotation
$(A)$ Dextrorotatory	$d$	$(+)$	Right
$(B)$ Laevorotatory	$l$	$(-)$	Left
$(C)$ Optically Inactive (Racemic)	$dl$	$(\pm)$	Zero rotation

What is the number of optical isomers for $2, 3-$dibromobutanoic acid?

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