The number of stereoisomers for the compound | vedclass

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(D) The given compound is $CH_3-CHBr-CHBr-COOH$. It contains two chiral carbon atoms at positions $C_2$ and $C_3$. The molecule is unsymmetrical becau

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$4$

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(D) The given compound is $CH_3-CHBr-CHBr-COOH$. It contains two chiral carbon atoms at positions $C_2$ and $C_3$. The molecule is unsymmetrical because the groups attached to the chiral carbons are different ($CH_3$ and $COOH$). For an unsymmetrical molecule with $n$ chiral centers,the number of stereoisomers is given by $2^n$. Here,$n = 2$,so the number of stereoisomers = $2^2 = 4$.

The number of stereoisomers for the compound $CH_3-CHBr-CHBr-COOH$ is ......... .

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