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(B) The molecular formula $C_3H_6ClBr$ corresponds to a degree of unsaturation of $0$,indicating a saturated acyclic compound. The structural isomers

Vedclass · Accepted Answer

$5, 3$

Vedclass · Answer

(B) The molecular formula $C_3H_6ClBr$ corresponds to a degree of unsaturation of $0$,indicating a saturated acyclic compound. The structural isomers are formed by placing the $Cl$ and $Br$ atoms on the propane chain:$1$. $1-bromo-1-chloropropane$: $CH_3-CH_2-CH(Cl)Br$ (Optically active)$2$. $1-bromo-2-chloropropane$: $CH_3-CH(Cl)-CH_2Br$ (Optically active)$3$. $1-bromo-3-chloropropane$: $Cl-CH_2-CH_2-CH_2Br$ (Optically inactive)$4$. $2-bromo-1-chloropropane$: $CH_3-CH(Br)-CH_2Cl$ (Optically active)$5$. $1-bromo-1-chloro-2-methyl$ (Not possible as it is $C_4$)Wait,let us list them systematically:- $1-bromo-1-chloropropane$ (Chiral at $C_1$)- $2-bromo-1-chloropropane$ (Chiral at $C_2$)- $1-bromo-2-chloropropane$ (Chiral at $C_2$)- $3-bromo-1-chloropropane$ (Achiral)- $2-bromo-2-chloropropane$ (Achiral)There are $5$ structural isomers. Among these,$3$ are optically active ($1-bromo-1-chloropropane$,$2-bromo-1-chloropropane$,and $1-bromo-2-chloropropane$).Thus,the correct answer is $5$ structural isomers and $3$ optically active isomers.

How many structural isomers are possible for $C_3H_6ClBr$ and how many of them are optically active?

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