In the S_{N}2 substitution reaction R-Br + Cl | vedclass

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(B) The rate of an $S_{N}2$ reaction is primarily governed by steric hindrance. $S_{N}2$ reactions proceed fastest with primary alkyl halides that hav

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$CH_3CH_2Br$

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(B) The rate of an $S_{N}2$ reaction is primarily governed by steric hindrance. $S_{N}2$ reactions proceed fastest with primary alkyl halides that have the least steric hindrance around the electrophilic carbon atom. Comparing the options: $(A)$ $(CH_3)_3C-CH_2Br$ is a primary alkyl halide but has significant steric hindrance due to the bulky tert-butyl group at the $\beta$-position. $(B)$ $CH_3CH_2Br$ is a primary alkyl halide with minimal steric hindrance. $(C)$ $CH_3CH_2CH_2Br$ is a primary alkyl halide with slightly more steric hindrance than ethyl bromide. $(D)$ $(CH_3)_2CH-CH_2Br$ is a primary alkyl halide with more steric hindrance than $(B)$ and $(C)$. Therefore,$CH_3CH_2Br$ reacts the fastest.

In the $S_{N}2$ substitution reaction $R-Br + Cl^- \xrightarrow{DMF} R-Cl + Br^-$,which of the following will have the highest rate?

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