The conversion of 2,3-dibromobutane to 2-bute | vedclass

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(C) The reaction of $2,3-$dibromobutane $(CH_3-CHBr-CHBr-CH_3)$ with $Zn$ dust in alcohol is a debromination reaction.In this reaction,two bromine ato

Vedclass · Accepted Answer

Both $\beta -$elimination and redox

Vedclass · Answer

(C) The reaction of $2,3-$dibromobutane $(CH_3-CHBr-CHBr-CH_3)$ with $Zn$ dust in alcohol is a debromination reaction.In this reaction,two bromine atoms are removed from adjacent carbon atoms,leading to the formation of a double bond between them.This process is classified as a $\beta -$elimination reaction because the leaving groups are on adjacent carbons.Additionally,the oxidation state of $Zn$ changes from $0$ to $+2$ (oxidation) and the bromine atoms in the organic molecule are reduced (reduction),making it a redox reaction as well.Therefore,it is both a $\beta -$elimination and a redox reaction.

The conversion of $2,3-$dibromobutane to $2-$butene using $Zn$ and alcohol is a/an .... reaction.

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