What will be the major product of the followi | vedclass

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(A) The substrate is a primary alkyl halide,$(CH_3)_2CH-CH_2Br$ (isobutyl bromide).The reagent is $CH_3O^- / CH_3OH$,which is a strong nucleophile and

Vedclass · Accepted Answer

$(CH_3)_2CH-CH_2OCH_3$

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(A) The substrate is a primary alkyl halide,$(CH_3)_2CH-CH_2Br$ (isobutyl bromide).The reagent is $CH_3O^- / CH_3OH$,which is a strong nucleophile and a strong base.For a primary alkyl halide,the $S_N2$ reaction is generally favored over $E2$ because there is less steric hindrance at the $\alpha$-carbon.Therefore,the nucleophile $CH_3O^-$ attacks the $\alpha$-carbon,displacing the bromide ion to form an ether.The major product is $(CH_3)_2CH-CH_2OCH_3$ (methyl isobutyl ether).

What will be the major product of the following reaction?
$(CH_3)_2CH-CH_2Br \xrightarrow{CH_3O^- / CH_3OH}$

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What will be the major product of the following reaction?$(CH_3)_2CH-CH_2Br \xrightarrow{CH_3O^- / CH_3OH}$