In the following reaction,the compound B will | vedclass

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(C) $1$. The reaction of ethyl bromide $(C_2H_5Br)$ with $KCN$ is a nucleophilic substitution reaction.$2$. $C_2H_5Br + KCN \rightarrow C_2H_5CN + KBr

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Propionic acid

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(C) $1$. The reaction of ethyl bromide $(C_2H_5Br)$ with $KCN$ is a nucleophilic substitution reaction.$2$. $C_2H_5Br + KCN \rightarrow C_2H_5CN + KBr$. Here,$A$ is ethyl cyanide $(C_2H_5CN)$.$3$. The hydrolysis of alkyl cyanides $(R-CN)$ yields carboxylic acids $(R-COOH)$.$4$. $C_2H_5CN + 2H_2O \xrightarrow{H^+} C_2H_5COOH + NH_3$.$5$. The product $B$ is propionic acid $(C_2H_5COOH)$.

In the following reaction,the compound $B$ will be:
$C_2H_5Br$ $\xrightarrow{KCN} A$ $\xrightarrow{\text{Hydrolysis}} B$

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In the following reaction,the compound $B$ will be:$C_2H_5Br$ $\xrightarrow{KCN} A$ $\xrightarrow{\text{Hydrolysis}} B$