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(A) $2$-bromopentane $(CH_3CH_2CH_2CH(Br)CH_3)$ undergoes dehydrohalogenation in the presence of a strong base like potassium ethoxide $(C_2H_5OK)$ in

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trans-pent-$2$-ene

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(A) $2$-bromopentane $(CH_3CH_2CH_2CH(Br)CH_3)$ undergoes dehydrohalogenation in the presence of a strong base like potassium ethoxide $(C_2H_5OK)$ in ethanol. According to Zaitsev's rule,the more substituted alkene is the major product. The reaction can proceed via $E2$ mechanism to form pent-$2$-ene. Since trans-pent-$2$-ene is more stable than cis-pent-$2$-ene due to less steric hindrance,it is the major product.

The major product obtained from the reaction of $2$-bromopentane with potassium ethoxide in ethanol is ....................

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The reaction of $2-$bromopentane with sodium ethoxide in ethanol yields ........

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$CH_3-CH(Br)-CH_3 \xrightarrow[\Delta]{\text{Alc. KOH}} A \xrightarrow[\text{Peroxide absent}]{\text{HBr}} B$

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