The reaction of $o-$methoxychlorobenzene with sodamide $(NaNH_2)$ followed by treatment with ammonia yields ........

  • A
    $p-$methoxyaniline
  • B
    $m-$methoxyaniline
  • C
    Aniline
  • D
    $o-$methoxyaniline

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$STATEMENT-1$: Bromobenzene upon reaction with $Br_2 / Fe$ gives $1,4$-dibromobenzene as the major product.
$STATEMENT-2$: In bromobenzene,the inductive effect of the bromo group is more dominant than the mesomeric effect in directing the incoming electrophile.

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