$CH_3 - C \equiv CH$ $\xrightarrow{Na} X$ $\xrightarrow{CH_3 - Cl} Y$,
$Y$ is

  • A
    $CH_3 - CH_2 - C \equiv CH$
  • B
    $CH_3 - C \equiv C - CH_3$
  • C
    $CH_3 - CH_2 - CH = CH_2$
  • D
    $CH_3 - CH = CH - CH_3$

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