The solid $AB$ has a $NaCl$ type structure. If the radius of the $A^{+}$ ion is $120 \, pm$, then the maximum radius of the $B^{-}$ ion will be ........... $pm$.

In $NaCl$ type structure, the shortest distance between two nearest neighbours is $100 \ pm$. Then, the distance between two next nearest neighbours in the same unit cell will be:

What is the number of atoms present in the unit cells of a simple cubic,body-centered cubic,and face-centered cubic lattice of a monoatomic substance,respectively?

$A$ compound is formed by elements $A$ and $B$. This crystallises in the cubic structure where the $A$ atoms are at the corners of the cube and $B$ atoms are at the body centres. The simplest formula of the compound is

What is the total number of atoms present in an $fcc$ unit cell?

The number of close neighbours in a body-centred cubic $(BCC)$ lattice of identical spheres is: