In a crystal of LiI, I^{-} ions are arranged | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The structure of $LiI$ is similar to $NaCl$ (rock salt structure).In this structure, the edge length $a$ is related to the ionic radii $r_{+}$ $(L

Vedclass · Accepted Answer

$85$

Vedclass · Answer

(D) The structure of $LiI$ is similar to $NaCl$ (rock salt structure).In this structure, the edge length $a$ is related to the ionic radii $r_{+}$ $(Li^{+})$ and $r_{-}$ $(I^{-})$ by the relation: $a = 2(r_{+} + r_{-})$.For $ccp$ arrangement of anions, the anions touch along the face diagonal: $4r_{-} = \sqrt{2}a$.Thus, $r_{-} = \frac{\sqrt{2}a}{4} = \frac{1.414 	imes 600}{4} = 212.1 \ pm$.Using the relation $a = 2(r_{+} + r_{-})$:$600 = 2(r_{+} + 212.1)$$300 = r_{+} + 212.1$$r_{+} = 300 - 212.1 = 87.9 \ pm \approx 88 \ pm$.The closest option is $85 \ pm$.

In a crystal of $LiI$, $I^{-}$ ions are arranged in a $ccp$ structure and $Li^{+}$ ions occupy octahedral voids. If $a = 600 \ pm$, what is the radius of the $Li^{+}$ ion in $pm$?

Similar Questions

In a face-centered cubic lattice of $X$ and $Y$ atoms,$X$ atoms are present at the corners while $Y$ atoms are at the face centers. If two atoms of $X$ are missing from the corners,what is the formula of the compound?

Which of the following structures is not correctly matched?

When a $CsCl$ type crystal is heated to a very high temperature,the coordination number of the cation becomes .....

The structure of $TlCl$ is similar to $CsCl$. What is the coordination number of $Tl^{+}$?

In solid $CsCl$,each $Cl^{-}$ ion is closely packed with how many $Cs^{+}$ ions?

Vedclass Test Series

Exam Paper Generator

Online Exam Module