Calculate the percentage of Fe^{+2} in Fe_{0. | vedclass

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(D) Let the total number of $Fe$ ions be $0.95$ and $O$ ions be $1$. Let the number of $Fe^{+2}$ ions be $x$. Then the number of $Fe^{+3}$ ions is $(0

Vedclass · Accepted Answer

$89.47$

Vedclass · Answer

(D) Let the total number of $Fe$ ions be $0.95$ and $O$ ions be $1$. Let the number of $Fe^{+2}$ ions be $x$. Then the number of $Fe^{+3}$ ions is $(0.95 - x)$. Since the compound is electrically neutral,the total positive charge must equal the total negative charge. $2x + 3(0.95 - x) = 2$ $2x + 2.85 - 3x = 2$ $-x = 2 - 2.85$ $-x = -0.85$ $x = 0.85$. Percentage of $Fe^{+2} = (\frac{0.85}{0.95}) 	imes 100 = 89.47\%$.

Calculate the percentage of $Fe^{+2}$ in $Fe_{0.95}O$.

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