$A$ metal oxide shows $p-$type semiconductivity. The conductivity of the oxide will increase by:

  • A
    Increasing the pressure of oxygen in contact with the oxide
  • B
    Decreasing the pressure of oxygen in contact with the oxide
  • C
    Conductivity is independent of oxygen pressure
  • D
    Conductivity increases because oxygen forms a $p-n$ junction

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Similar Questions

$NaCl$ is doped with $2 \times 10^{-3} \, mol \% \, SrCl_2$. What is the concentration of cation vacancies?

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In a solid lattice,the cation has left a lattice site and is located at an interstitial position. The lattice defect is:

The correct statement regarding defects in crystalline solids is

If $10^{-4} \, \text{mole} \%$ of $SrCl_2$ is added to $NaCl$,the concentration of cation vacancies created is...... $(N_A = 6.02 \times 10^{23} \, \text{mol}^{-1})$

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As a result of Schottky defect,the density of the crystal:

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