What is the mole fraction of water in a spiri | vedclass

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(C) Given: $92\%$ ethyl alcohol by mass means $92 \ g$ of $C_2H_5OH$ in $100 \ g$ of solution.Mass of $C_2H_5OH = 92 \ g$,Mass of $H_2O = 100 - 92 = 8

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$0.18$

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(C) Given: $92\%$ ethyl alcohol by mass means $92 \ g$ of $C_2H_5OH$ in $100 \ g$ of solution.Mass of $C_2H_5OH = 92 \ g$,Mass of $H_2O = 100 - 92 = 8 \ g$.Molar mass of $C_2H_5OH = (2 	imes 12) + (6 	imes 1) + 16 = 46 \ g/mol$.Molar mass of $H_2O = (2 	imes 1) + 16 = 18 \ g/mol$.Moles of $C_2H_5OH (n_{alc}) = \frac{92}{46} = 2 \ mol$.Moles of $H_2O (n_{water}) = \frac{8}{18} = 0.444 \ mol$.Mole fraction of water $(x_{water}) = \frac{n_{water}}{n_{water} + n_{alc}} = \frac{0.444}{0.444 + 2} = \frac{0.444}{2.444} \approx 0.18$.

What is the mole fraction of water in a spirit sample containing $92\%$ ethyl alcohol by mass?

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