Benzene and toluene form an ideal solution. If the partial vapor pressures of benzene and toluene are $1.55 \ kPa$ and $1.85 \ kPa$ respectively,what is the mole ratio of benzene to toluene in the solution?

What is meant by positive and negative deviations from Raoult's law and how is the sign of $\Delta_{mix} H$ related to positive and negative deviations from Raoult's law?

Liquids $A$ and $B$ form an ideal solution in the entire composition range. At $350 \ K$,the vapour pressures of pure $A$ and pure $B$ are $7 \times 10^3 \ Pa$ and $12 \times 10^3 \ Pa$,respectively. The composition of the vapour in equilibrium with a solution containing $40 \ \text{mole percent}$ of $A$ at this temperature is

At a particular temperature,the vapour pressures of two liquids $A$ and $B$ are respectively $120 \, mm$ and $180 \, mm$ of mercury. If $2 \, moles$ of $A$ and $3 \, moles$ of $B$ are mixed to form an ideal solution,the vapour pressure of the solution at the same temperature will be (in $mm$ of mercury):

$A$ liquid solution is formed by mixing $10 \, moles$ of aniline and $20 \, moles$ of phenol at a temperature where the vapour pressure of pure liquid aniline and phenol are $90 \, mmHg$ and $87 \, mmHg$ respectively. The possible vapour pressure of the solution at that temperature is ............. $mmHg$.

At $88 \, ^\circ C$,the vapor pressure of benzene is $900 \, \text{torr}$ and the vapor pressure of toluene is $360 \, \text{torr}$. What is the mole fraction of benzene in the mixture with toluene at $1 \, \text{atm}$ and $88 \, ^\circ C$? Assume benzene and toluene form an ideal solution.