Which of the following aqueous solutions will | vedclass

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(A) The elevation in boiling point $(\Delta T_b)$ is a colligative property,which depends on the van't Hoff factor $(i)$ and the molar concentration $

Vedclass · Accepted Answer

$0.01 \, M \, Na_2SO_4$

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(A) The elevation in boiling point $(\Delta T_b)$ is a colligative property,which depends on the van't Hoff factor $(i)$ and the molar concentration $(C)$: $\Delta T_b = i 	imes K_b 	imes C$. For $0.01 \, M \, Na_2SO_4$,$i = 3$ $(2Na^    SO_4^{2-})$,so effective concentration = $3 	imes 0.01 = 0.03 \, M$. For $0.01 \, M \, KNO_3$,$i = 2$ $(K^    NO_3^-)$,so effective concentration = $2 	imes 0.01 = 0.02 \, M$. For $0.015 \, M \, 	ext{urea}$,$i = 1$ (non-electrolyte),so effective concentration = $1 	imes 0.015 = 0.015 \, M$. For $0.015 \, M \, 	ext{glucose}$,$i = 1$ (non-electrolyte),so effective concentration = $1 	imes 0.015 = 0.015 \, M$. Since $0.01 \, M \, Na_2SO_4$ has the highest effective concentration $(0.03 \, M)$,it will have the highest boiling point.

Which of the following aqueous solutions will have the highest boiling point?

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