40 mg of pure sodium hydroxide is dissolved | vedclass

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(B) Step $1$: Calculate the molar mass of $NaOH = 23 + 16 + 1 = 40 \ g/mol$. Step $2$: Calculate the number of moles of $NaOH = \frac{	ext{mass}}{	e

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$10$

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(B) Step $1$: Calculate the molar mass of $NaOH = 23 + 16 + 1 = 40 \ g/mol$. Step $2$: Calculate the number of moles of $NaOH = \frac{	ext{mass}}{	ext{molar mass}} = \frac{40 	imes 10^{-3} \ g}{40 \ g/mol} = 10^{-3} \ mol$. Step $3$: Calculate the concentration of $OH^-$ ions: $[OH^-] = \frac{	ext{moles}}{	ext{volume in L}} = \frac{10^{-3} \ mol}{10 \ L} = 10^{-4} \ M$. Step $4$: Calculate $pOH = -\log[OH^-] = -\log(10^{-4}) = 4$. Step $5$: Calculate $pH = 14 - pOH = 14 - 4 = 10$.

$40 \ mg$ of pure sodium hydroxide is dissolved in $10 \ L$ of distilled water. The $p^H$ of the solution is ..........

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