The dissociation constant of $NH_4OH$ is $1.8 \times 10^{-5}$. Calculate the hydrolysis constant of $NH_4Cl$.

  • A
    $1.8 \times 10^{-19}$
  • B
    $5.55 \times 10^{-10}$
  • C
    $5.55 \times 10^{-5}$
  • D
    $1.8 \times 10^{-5}$

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