The reaction of methanol $(\Delta H_f^o = -238.7 \ kJ \ mol^{-1})$ with $2$-methylpropene produces methyl tert-butyl ether $(\Delta H_f^o = -313.6 \ kJ \ mol^{-1})$. Given the reaction: $(CH_3)_2C = CH_2 + CH_3OH \rightarrow (CH_3)_3C - OCH_3; \Delta H^o = -57.8 \ kJ \ mol^{-1}$,calculate the $\Delta H_f^o$ for $2$-methylpropene.
- A$-17.1 \ kJ \ mol^{-1}$
- B$23.4 \ kJ \ mol^{-1}$
- C$8.6 \ kJ \ mol^{-1}$
- D$-20.68 \ kJ \ mol^{-1}$
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