Glucose xrightarrow{HCN} A xrightarrow{Hydrol | vedclass

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(C) $1$. Glucose $(CHO(CHOH)_4CH_2OH)$ reacts with $HCN$ to form a cyanohydrin $(A)$: $CHO(CHOH)_4CH_2OH + HCN \rightarrow CH(OH)(CN)(CHOH)_4CH_2OH$.$

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Heptane

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(C) $1$. Glucose $(CHO(CHOH)_4CH_2OH)$ reacts with $HCN$ to form a cyanohydrin $(A)$: $CHO(CHOH)_4CH_2OH + HCN \rightarrow CH(OH)(CN)(CHOH)_4CH_2OH$.$2$. Hydrolysis of the cyanohydrin $(A)$ yields a carboxylic acid $(B)$: $CH(OH)(COOH)(CHOH)_4CH_2OH$.$3$. Reduction of the carboxylic acid $(B)$ with $HI$ and red phosphorus $(\Delta)$ reduces all hydroxyl groups and the carboxylic acid group to a straight-chain alkane. The resulting product is $n$-heptane $(C)$.

Glucose $\xrightarrow{HCN} A$ $\xrightarrow{Hydrolysis} B$ $\xrightarrow{HI, \Delta} C$. What is the final product $C$?

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