What is the formula of meta-boric acid?

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Question

(A) Orthoboric acid $(H_3BO_3)$ on heating at $370 \ K$ loses a water molecule to form meta-boric acid $(HBO_2)$.The reaction is: $H_3BO_3 \xrightarro

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$HBO_2$

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(A) Orthoboric acid $(H_3BO_3)$ on heating at $370 \ K$ loses a water molecule to form meta-boric acid $(HBO_2)$.The reaction is: $H_3BO_3 \xrightarrow{\Delta, 370 \ K} HBO_2 + H_2O$.

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