Which of the following statements is incorrec | vedclass

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(D) $1$. $CO_2$ is a linear molecule with $sp$ hybridization at the carbon atom,making it non-polar due to the cancellation of dipole moments.$2$. $H_

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In $CO_2$ and its dihydrate molecule $H_2CO_3$,the carbon atom is in $sp^2$ hybridization.

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(D) $1$. $CO_2$ is a linear molecule with $sp$ hybridization at the carbon atom,making it non-polar due to the cancellation of dipole moments.$2$. $H_2CO_3$ (carbonic acid) is formed by the reaction of $CO_2$ with water $(CO_2 + H_2O \rightarrow H_2CO_3)$.$3$. In $CO_2$,carbon is $sp$ hybridized. In $H_2CO_3$,the carbon atom is $sp^2$ hybridized because it is bonded to three oxygen atoms (one double bond and two single bonds).$4$. Therefore,the statement that carbon is $sp^2$ hybridized in both $CO_2$ and $H_2CO_3$ is incorrect.

List-$I$ (Molecule Species)	List-$II$ (Property/Shape)
$A$. $SO_2Cl_2$	$I$. Paramagnetic
$B$. $NO$	$II$. Diamagnetic
$C$. $NO_2^-$	$III$. Tetrahedral
$D$. $I_3^-$	$IV$. Linear

Which of the following statements is incorrect?

Similar Questions

The correct order as indicated in each option is

The formal charges of atoms $(1)$,$(2)$ and $(3)$ in the ion $[\underset{(1)}{O}=\underset{(2)}{N}=\underset{(3)}{O}]^{+}$ are:

Choose the correct order for the given properties.

Match List-$I$ with List-$II$ :

List-$I$ (Molecule Species) List-$II$ (Property/Shape)

$A$. $SO_2Cl_2$ $I$. Paramagnetic

$B$. $NO$ $II$. Diamagnetic

$C$. $NO_2^-$ $III$. Tetrahedral

$D$. $I_3^-$ $IV$. Linear

Choose the correct answer from the options given below :

Total number of compounds / ions which have at least two bond lengths same out of $CO_3^{2-}, HCOOH, S_2O_3^{2-}, NO_2^{-}$

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