$Ge(II)$ compounds are strong reducing agents,whereas $Pb(IV)$ compounds are strong oxidizing agents. This is due to.........

• A
  $Pb$ is more electropositive than $Ge$
• B
  The ionization potential of $Pb$ is lower than that of $Ge$
• C
  The ionic radii of $Pb^{2+}$ and $Pb^{4+}$ are larger than those of $Ge^{2+}$ and $Ge^{4+}$
• D
  The inert pair effect is more pronounced in $Pb$ than in $Ge$