What is the hybridization of the central atom | vedclass

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(B) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence el

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$sp^3$

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(B) The hybridization of the central atom can be calculated using the formula: $H = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $NH_4^+$,the central atom is $N$ $(V = 5)$,$M = 4$ (four $H$ atoms),$C = 1$,and $A = 0$.$H = \frac{1}{2} (5 + 4 - 1 + 0) = \frac{8}{2} = 4$.$A$ value of $4$ corresponds to $sp^3$ hybridization.

What is the hybridization of the central atom in $NH_4^+$?

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