When SO_2 gas is passed through an acidic sol | vedclass

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(D) When $SO_2$ gas is passed through an acidic solution of potassium dichromate $(K_2Cr_2O_7)$,the orange-colored dichromate ion $(Cr_2O_7^{2-})$ is

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$A$ green colored $Cr_2(SO_4)_3$ is formed.

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(D) When $SO_2$ gas is passed through an acidic solution of potassium dichromate $(K_2Cr_2O_7)$,the orange-colored dichromate ion $(Cr_2O_7^{2-})$ is reduced to green-colored chromium$(III)$ sulfate $(Cr_2(SO_4)_3)$.The chemical reaction is:$K_2Cr_2O_7 + H_2SO_4 + 3SO_2 \rightarrow K_2SO_4 + Cr_2(SO_4)_3 + H_2O$.In this reaction,$Cr^{6+}$ is reduced to $Cr^{3+}$,which imparts a green color to the solution.

When $SO_2$ gas is passed through an acidic solution of $K_2Cr_2O_7$,what happens?

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