Which of the following does not have sp^3 hyb | vedclass

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(A) $1$. In $SO_2$,the central atom $S$ has one lone pair and two bond pairs (double bonds). The steric number is $1 + 2 = 3$,which corresponds to $sp

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$SO_2$

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(A) $1$. In $SO_2$,the central atom $S$ has one lone pair and two bond pairs (double bonds). The steric number is $1 + 2 = 3$,which corresponds to $sp^2$ hybridization.$2$. In $CH_4$,the central atom $C$ has four bond pairs. The steric number is $4$,which corresponds to $sp^3$ hybridization.$3$. In $NH_3$,the central atom $N$ has one lone pair and three bond pairs. The steric number is $1 + 3 = 4$,which corresponds to $sp^3$ hybridization.$4$. In $SO_4^{2-}$,the central atom $S$ has four bond pairs. The steric number is $4$,which corresponds to $sp^3$ hybridization.Therefore,$SO_2$ does not have $sp^3$ hybridization.

Which of the following does not have $sp^3$ hybridization?

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