Which of the following is the strongest reduc | vedclass

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Question

(A) The reducing character of hydrogen halides depends on the bond dissociation enthalpy of the $H-X$ bond. As the size of the halogen atom increases

Vedclass · Accepted Answer

$HI$

Vedclass · Answer

(A) The reducing character of hydrogen halides depends on the bond dissociation enthalpy of the $H-X$ bond. As the size of the halogen atom increases from $F$ to $I$,the bond length increases and the bond dissociation enthalpy decreases. Therefore,the order of bond dissociation enthalpy is $HF > HCl > HBr > HI$. Since $HI$ has the weakest bond,it can easily release $H^+$ and $e^-$,making it the strongest reducing agent among the given options.

Which of the following is the strongest reducing agent?

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