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(C) Let us analyze the reactions of the given pairs with water:$1$. For $Ca$ and $CaH_2$:$Ca + 2H_2O \rightarrow Ca(OH)_2 + H_2(g)$$CaH_2 + 2H_2O \rig

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$Ca$ and $CaH_2$

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(C) Let us analyze the reactions of the given pairs with water:$1$. For $Ca$ and $CaH_2$:$Ca + 2H_2O \rightarrow Ca(OH)_2 + H_2(g)$$CaH_2 + 2H_2O \rightarrow Ca(OH)_2 + 2H_2(g)$Both reactions produce hydrogen gas $(H_2)$ as the gaseous product.$2$. For other options:$K$ produces $H_2$,while $KO_2$ produces $O_2$.$Na$ produces $H_2$,while $Na_2O_2$ produces $H_2O_2$ (which decomposes to $O_2$).$Ba$ produces $H_2$,while $BaO_2$ produces $H_2O_2$ (which decomposes to $O_2$).Therefore,the pair that produces the same gaseous product $(H_2)$ is $Ca$ and $CaH_2$.

All of the following substances react with water. Which pair among them will produce the same gaseous product upon reaction with water?

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