100 , cm^3 of gold sol requires 10^{-4} , g o | vedclass

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Question

(D) The gold number is defined as the minimum amount of protective colloid in milligrams $(mg)$ required to prevent the coagulation of $10 \, mL$ of a

Vedclass · Accepted Answer

$0.01$

Vedclass · Answer

(D) The gold number is defined as the minimum amount of protective colloid in milligrams $(mg)$ required to prevent the coagulation of $10 \, mL$ of a standard gold sol when $1 \, mL$ of $10 \% \, NaCl$ solution is added. Given that $100 \, cm^3$ of gold sol requires $10^{-4} \, g$ of gelatin. Therefore,$10 \, cm^3$ of gold sol requires $\frac{10^{-4}}{10} \, g = 10^{-5} \, g$ of gelatin. Converting $g$ to $mg$: $10^{-5} \, g = 10^{-5} 	imes 10^3 \, mg = 10^{-2} \, mg = 0.01 \, mg$. Thus,the gold number of gelatin is $0.01$.

List-$I$	List-$II$
$A$. Dialysis	$IV$. Purification of colloidal mixture
$B$. Peptization	$I$. Precipitate converts to colloidal mixture
$C$. Flocculation	$II$. Precipitation of colloidal mixture
$D$. Gold number	$III$. Protective power

$100 \, cm^3$ of gold sol requires $10^{-4} \, g$ of gelatin to prevent coagulation when $1 \, cm^3$ of $10 \% \, NaCl$ solution is added. The gold number of gelatin is ............ .

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Match the following:-

List-$I$ List-$II$

$A$. Dialysis $IV$. Purification of colloidal mixture

$B$. Peptization $I$. Precipitate converts to colloidal mixture

$C$. Flocculation $II$. Precipitation of colloidal mixture

$D$. Gold number $III$. Protective power

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