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(D) Step $1$: Phenol reacts with $Zn$ dust to form Benzene $(A)$.$	ext{C}_6H_5OH + Zn ightarrow C_6H_6 + ZnO$Step $2$: Benzene undergoes nitration

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Benzene,Nitrobenzene,and Hydrazobenzene

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(D) Step $1$: Phenol reacts with $Zn$ dust to form Benzene $(A)$.$	ext{C}_6H_5OH + Zn ightarrow C_6H_6 + ZnO$Step $2$: Benzene undergoes nitration with conc. $HNO_3$ and conc. $H_2SO_4$ at $60^{\circ}C$ to form Nitrobenzene $(B)$.$C_6H_6 + HNO_3 \xrightarrow{H_2SO_4} C_6H_5NO_2 + H_2O$Step $3$: Nitrobenzene is reduced by $Zn$ in the presence of aqueous $NaOH$ to form Hydrazobenzene $(C)$.$2C_6H_5NO_2 + 5Zn + 10NaOH ightarrow C_6H_5NH-NHC_6H_5 + 5Na_2ZnO_2 + 4H_2O$

What will be the products $A$,$B$,and $C$ in the following reaction sequence?
$\text{Phenol}$ $\xrightarrow[\text{Distillation}]{\text{Zn}} A$ $\xrightarrow[\text{conc. } H_2SO_4]{\text{conc. } HNO_3, 60^{\circ}C} B$ $\xrightarrow[\text{NaOH (aq)}]{\text{Zn}} C$

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What will be the products $A$,$B$,and $C$ in the following reaction sequence?$\text{Phenol}$ $\xrightarrow[\text{Distillation}]{\text{Zn}} A$ $\xrightarrow[\text{conc. } H_2SO_4]{\text{conc. } HNO_3, 60^{\circ}C} B$ $\xrightarrow[\text{NaOH (aq)}]{\text{Zn}} C$