p-Cresol reacts with chloroform in an alkalin | vedclass

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(A) $1$. $p-$Cresol reacts with $CHCl_3$ in an alkaline medium (Reimer-Tiemann reaction) to form $2-$hydroxy$-5-$methylbenzaldehyde (compound $A$).$2$

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(A) $1$. $p-$Cresol reacts with $CHCl_3$ in an alkaline medium (Reimer-Tiemann reaction) to form $2-$hydroxy$-5-$methylbenzaldehyde (compound $A$).$2$. Compound $A$ reacts with $HCN$ to form a cyanohydrin,$2-$hydroxy$-5-$methylmandelonitrile (compound $Y$).$3$. Hydrolysis of the cyanohydrin group $(-CN)$ yields a carboxylic acid group $(-COOH)$.$4$. The resulting product is $2-$hydroxy$-5-$methylmandelic acid,which has a chiral center at the carbon atom attached to the $-OH$ and $-COOH$ groups.$5$. The structure is a benzene ring with a $-CH_3$ group at position $1$,an $-OH$ group at position $4$,and a $-CH(OH)COOH$ group at position $2$.

$p-$Cresol reacts with chloroform in an alkaline medium to give compound $A$,which reacts with hydrogen cyanide to form compound $Y$. Hydrolysis of $Y$ gives a chiral carboxylic acid. Identify the structure of the carboxylic acid.

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