What is obtained when phenol is treated with excess bromine water?

Identify the product obtained in the following reaction:
$C_6H_5OH \xrightarrow{CrO_3} \text{Product}$

In the presence of $NaOH$,phenol reacts with $CHCl_3$ to form $o$-hydroxybenzaldehyde. This reaction is called:

The reactant is $4-hydroxy-3-methylbenzenesulfonic acid$. The reaction with $Br_2$ in $H_2O$ (bromine water) is an electrophilic aromatic substitution. The $-OH$ group is strongly activating and ortho/para directing. The $-SO_3H$ group is a good leaving group in the presence of excess bromine water. Predict the product of the reaction: $\xrightarrow{Br_2, H_2O} \text{Product}$

Which one of the following phenols does not give colour when condensed with phthalic anhydride in the presence of conc. $H_2SO_4$?

The correct order of acid strength of the following compounds is:
$A$. Phenol
$B$. $p$-Cresol
$C$. $m$-Nitrophenol
$D$. $p$-Nitrophenol