An organic compound with the molecular formula $C_4H_{10}O$ does not react with sodium metal and produces only two types of halides upon reaction with excess $HI$. What is the compound?

  • A
    Ethoxyethane
  • B
    $2-$Methylpropan$-2-$ol
  • C
    $1-$Methoxypropane
  • D
    $1-$Butanol

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Complete the following reaction:
$CH_3CH_2-O-C(CH_3)_2-CH_2CH_3 + \text{conc. } HI \to (?)$

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