In which of the following pairs is the differ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To find the difference in oxidation numbers,we calculate the oxidation state of the underlined element in each compound:$A$: In $\underline{N}O_2$

Vedclass · Accepted Answer

$\underline{N}O_2$ and $\underline{N}_2H_4$

Vedclass · Answer

(A) To find the difference in oxidation numbers,we calculate the oxidation state of the underlined element in each compound:$A$: In $\underline{N}O_2$,$x + 2(-2) = 0 \implies x = +4$. In $\underline{N}_2H_4$,$2x + 4(+1) = 0 \implies 2x = -4 \implies x = -2$. Difference = $|4 - (-2)| = 6$.$B$: In $\underline{P}_2O_5$,$2x + 5(-2) = 0 \implies 2x = 10 \implies x = +5$. In $\underline{P}_4O_{10}$,$4x + 10(-2) = 0 \implies 4x = 20 \implies x = +5$. Difference = $|5 - 5| = 0$.$C$: In $\underline{N}_2O$,$2x + (-2) = 0 \implies 2x = 2 \implies x = +1$. In $\underline{N}O$,$x + (-2) = 0 \implies x = +2$. Difference = $|2 - 1| = 1$.$D$: In $\underline{S}O_2$,$x + 2(-2) = 0 \implies x = +4$. In $\underline{S}O_3$,$x + 3(-2) = 0 \implies x = +6$. Difference = $|6 - 4| = 2$.Comparing the differences $(6, 0, 1, 2)$,the greatest difference is $6$ in option $A$.

In which of the following pairs is the difference in the oxidation number of the underlined elements the greatest?

Similar Questions

Determine the oxidation state of $Cr$ in $K_2Cr_2O_7$.

What is the oxidation state of oxygen in $OF_2$ and in $KO_2$ respectively?

The oxidation number of carbon in $CH_2Cl_2$ is .........

In which of the following compounds is the maximum oxidation state of the central atom present?

Explain the Stock notation theory with examples.

Vedclass Test Series

Exam Paper Generator

Online Exam Module