In the reaction between BaO_2 and H_2SO_4,the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The chemical reaction is: $BaO_2 + H_2SO_4 \longrightarrow BaSO_4 + H_2O_2$. In the products $BaSO_4$ and $H_2O_2$,the most electronegative elemen

Vedclass · Accepted Answer

$-1$ and $-2$

Vedclass · Answer

(B) The chemical reaction is: $BaO_2 + H_2SO_4 \longrightarrow BaSO_4 + H_2O_2$. In the products $BaSO_4$ and $H_2O_2$,the most electronegative element is oxygen $(O)$. In $BaSO_4$,the oxidation state of oxygen is $-2$. In $H_2O_2$ (hydrogen peroxide),the oxidation state of oxygen is $-1$. Thus,the oxidation states of the most electronegative element (oxygen) in the products are $-2$ and $-1$.

In the reaction between $BaO_2$ and $H_2SO_4$,the oxidation state of the most electronegative element in the products is .......

Similar Questions

The strengths of $5.6$ volume hydrogen peroxide (of density $1 \ g/mL$) in terms of mass percentage and molarity $(M)$,respectively,are:
(Take molar mass of hydrogen peroxide as $34 \ g/mol$)

Which of the following is known as 'Oxone'?

Which of the following gives $H_2O_2$ upon oxidation?

Which of the following can reduce the decomposition of $H_2O_2$ on exposure to light?

Phosphoric acid is preferred over sulphuric acid in preparing hydrogen peroxide from peroxides. Why?

Vedclass Test Series

Exam Paper Generator

Online Exam Module