Assertion : A quick collision between two bod | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Newton's second law,the impulsive force $F$ is given by $F = \frac{\Delta p}{\Delta t}$,where $\Delta p$ is the change in momentum an

Vedclass · Accepted Answer

If both $Assertion$ and $Reason$ are correct and the $Reason$ is a correct explanation of the $Assertion$.

Vedclass · Answer

(A) According to Newton's second law,the impulsive force $F$ is given by $F = \frac{\Delta p}{\Delta t}$,where $\Delta p$ is the change in momentum and $\Delta t$ is the time duration of the collision.In a quick collision,the time duration $\Delta t$ is very small.Since the change in momentum $\Delta p$ is the same for both cases (as initial and final velocities are identical),the force $F$ is inversely proportional to $\Delta t$ $(F \propto \frac{1}{\Delta t})$.Therefore,for a smaller $\Delta t$,the force $F$ is much larger,making the collision more violent.The rate of change of momentum is defined as $\frac{\Delta p}{\Delta t}$,which is exactly the force $F$.Since $\Delta t$ is smaller in the first case,the rate of change of momentum is indeed greater.Thus,both the $Assertion$ and $Reason$ are correct,and the $Reason$ is the correct explanation of the $Assertion$.

$Assertion$ : $A$ quick collision between two bodies is more violent than a slow collision,even when the initial and final velocities are identical.
$Reason$ : The rate of change of momentum is greater in the first case.

Similar Questions

The $F-t$ graph for an object is shown in the figure. What will be the magnitude of the change in momentum $(\Delta p)$ in the interval of $0.03\, s$ from the start?

$A$ cricket ball of mass $250\, g$ collides with a bat with velocity $10\, m/s$ and returns with the same velocity within $0.01\, s$. The force exerted on the ball is ....... $N$.

$A$ ball of mass $m$ moving with velocity $v_0$ collides with a wall as shown in the figure. After impact,it rebounds with a velocity $\frac{3}{4}v_0$. The impulse acting on the ball during the impact is

The position-time $(x-t)$ graph of a moving body of mass $2 \, kg$ is shown in the figure. The impulse on the body at $t=4 \, s$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

$Assertion$ : $A$ quick collision between two bodies is more violent than a slow collision,even when the initial and final velocities are identical.$Reason$ : The rate of change of momentum is greater in the first case.