Assertion: The time period of a simple pendul | vedclass

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(A) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$,where $g_{eff}$ is the effective acceleration due

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

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(A) The time period of a simple pendulum is given by the formula $T = 2\pi \sqrt{\frac{l}{g_{eff}}}$,where $g_{eff}$ is the effective acceleration due to gravity. Inside an orbiting satellite,the body is in a state of weightlessness,which means the effective acceleration due to gravity $g_{eff} = 0$. Substituting $g_{eff} = 0$ into the formula,we get $T = 2\pi \sqrt{\frac{l}{0}} = \infty$. Thus,the Assertion is correct. The Reason states that the time period is inversely proportional to $\sqrt{g}$,which is mathematically correct based on the formula $T \propto \frac{1}{\sqrt{g}}$. Since the infinite time period is a direct consequence of $g_{eff} = 0$ in the formula,the Reason correctly explains the Assertion.

$Assertion:$ The time period of a simple pendulum on a satellite orbiting the Earth is infinity.
$Reason:$ The time period of a simple pendulum is inversely proportional to $\sqrt{g}$.

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$Assertion:$ The time period of a simple pendulum on a satellite orbiting the Earth is infinity. $Reason:$ The time period of a simple pendulum is inversely proportional to $\sqrt{g}$.