KMnO_4 reacts with oxalic acid according to t | vedclass

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(C) From the balanced chemical equation,$2 \ 	ext{moles}$ of $KMnO_4$ react with $5 \ 	ext{moles}$ of $H_2C_2O_4$.Using the concept of milliequivale

Vedclass · Accepted Answer

$50 \ mL$ of $0.1 \ M \ H_2C_2O_4$

Vedclass · Answer

(C) From the balanced chemical equation,$2 \ 	ext{moles}$ of $KMnO_4$ react with $5 \ 	ext{moles}$ of $H_2C_2O_4$.Using the concept of milliequivalents (Meq):$	ext{Meq of } KMnO_4 = 	ext{Molarity} 	imes n	ext{-factor} 	imes 	ext{Volume (mL)}$For $KMnO_4$,the $n$-factor is $5$ $(Mn^{+7} 	o Mn^{+2})$.$	ext{Meq of } KMnO_4 = 0.1 	imes 5 	imes 20 = 10 \ 	ext{Meq}$.For $H_2C_2O_4$,the $n$-factor is $2$ $(C_2^{+3} 	o 2C^{+4} + 2e^-)$.We need $10 \ 	ext{Meq}$ of $H_2C_2O_4$.$	ext{Meq} = 	ext{Molarity} 	imes 2 	imes 	ext{Volume (mL)} = 10$.Checking option $(C)$: $50 \ mL$ of $0.1 \ M \ H_2C_2O_4$:$	ext{Meq} = 0.1 	imes 2 	imes 50 = 10 \ 	ext{Meq}$.Thus,$20 \ mL$ of $0.1 \ M \ KMnO_4$ is equivalent to $50 \ mL$ of $0.1 \ M \ H_2C_2O_4$.

List-$I$	List-$II$
$A$. $TiCl_{4(l)} + 2Mg_{(s)} \xrightarrow{\Delta} Ti_{(s)} + 2MgCl_{2(s)}$	$I$. Disproportionation reaction
$B$. $2H_2O_{2(aq)} \rightarrow 2H_2O_{(l)} + O_{2(g)}$	$II$. Metal displacement reaction
$C$. $C_{(s)} + O_{2(g)} \xrightarrow{\Delta} CO_{2(g)}$	$III$. Decomposition reaction
$D$. $2NaH_{(s)} \xrightarrow{\Delta} 2Na_{(s)} + H_{2(g)}$	$IV$. Combination reaction

$KMnO_4$ reacts with oxalic acid according to the equation:
$2MnO_4^- + 5C_2O_4^{2-} + 16H^+ \to 2Mn^{2+} + 10CO_2 + 8H_2O$
Here $20 \ mL$ of $0.1 \ M \ KMnO_4$ is equivalent to:

Similar Questions

Which of the following is not correct?

How many electrons $(e^-)$ are gained by the oxidizing agent $KMnO_4$ to convert into $MnO_4^{2-}$,$MnO_2$,$Mn_2O_3$,and $Mn^{2+}$ respectively?

$I^{-}(aq.) + MnO_4^{-}(aq.) \xrightarrow{H^{+}} X + Mn^{2+}(aq.)$
$I^{-}(aq.) + MnO_4^{-}(aq.) \xrightarrow{\text{Neutral or weakly } OH^{-}} Y + MnO_2$
$MnO_4^{-}(aq.) + Mn^{2+}(aq.) \xrightarrow{ZnSO_4} Z + 4H^{+}$
Products $X, Y$ and $Z$ are respectively :

Which of the following reactions does not involve either oxidation or reduction?

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$KMnO_4$ reacts with oxalic acid according to the equation:$2MnO_4^- + 5C_2O_4^{2-} + 16H^+ \to 2Mn^{2+} + 10CO_2 + 8H_2O$Here $20 \ mL$ of $0.1 \ M \ KMnO_4$ is equivalent to: