(CH_3)_2C = CHCH_3 + NOBr to product. The str | vedclass

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(B) The reaction follows the Markownikoff rule,where the electrophilic part $(NO^+)$ adds to the carbon atom with more hydrogen atoms,and the nucleoph

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$(CH_3)_2C(Br) - CH(NO)CH_3$

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(B) The reaction follows the Markownikoff rule,where the electrophilic part $(NO^+)$ adds to the carbon atom with more hydrogen atoms,and the nucleophilic part $(Br^-)$ adds to the carbon atom with fewer hydrogen atoms.In the reactant $(CH_3)_2C = CHCH_3$,the carbon at position $2$ has no hydrogen atoms,while the carbon at position $3$ has one hydrogen atom.Therefore,the $Br$ atom attaches to the carbon at position $2$,and the $NO$ group attaches to the carbon at position $3$.The product formed is $(CH_3)_2C(Br) - CH(NO)CH_3$.

$(CH_3)_2C = CHCH_3 + NOBr \to$ product. The structure of the product is

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