(C) The reaction between $H_2S$ and halogens ($X_2$,where $X = Cl, Br, I$) is given by the equation: $H_2S + X_2 \to 2HX + S$. In this reaction,the ox

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(C) The reaction between $H_2S$ and halogens ($X_2$,where $X = Cl, Br, I$) is given by the equation: $H_2S + X_2 \to 2HX + S$. In this reaction,the oxidation state of the halogen decreases from $0$ in $X_2$ to $-1$ in $HX$. Therefore,the halogens are reduced.