H_2S acts only as a reducing agent while SO_2 | vedclass

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Question

(D) In $H_2S$,the oxidation state of sulphur is $-2$,which is its minimum possible oxidation state,so it can only be oxidized (act as a reducing agent

Vedclass · Accepted Answer

Both $(a)$ and $(b)$

Vedclass · Answer

(D) In $H_2S$,the oxidation state of sulphur is $-2$,which is its minimum possible oxidation state,so it can only be oxidized (act as a reducing agent).In $SO_2$,the oxidation state of sulphur is $+4$,which is intermediate between its minimum $(-2)$ and maximum $(+6)$ oxidation states,allowing it to act as both an oxidizing agent (by decreasing its oxidation state) and a reducing agent (by increasing its oxidation state).

$H_2S$ acts only as a reducing agent while $SO_2$ can act both as a reducing and oxidizing agent because

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