Given the reactions at $500 \ K$:
$(i) \ H_{2(g)} + 1/2 O_{2(g)} \rightleftharpoons H_2O_{(g)}$,$K_c = 2.4 \times 10^{47}$
$(ii) \ H_2O_{(g)} \rightleftharpoons H_{2(g)} + 1/2 O_{2(g)}$,$K_c = 4.1 \times 10^{-48}$
What does the magnitude of $K_c$ indicate about the formation of the product in reaction $(i)$?

  • A
    The product is highly stable and formed in large amounts.
  • B
    The product is unstable and decomposes rapidly.
  • C
    The reaction does not proceed to form the product.
  • D
    The reaction is at equilibrium with equal amounts of reactants and products.

Explore More

Similar Questions

For a reversible reaction,if the concentration of reactants is increased,the equilibrium constant of the reaction

One mole of $A_{(g)}$ is heated to $200^{\circ} C$ in a one litre closed flask,until the following equilibrium is reached:
$A_{(g)} \rightleftharpoons B_{(g)}$
The rate of forward reaction at equilibrium is $0.02 \ mol \ L^{-1} \ min^{-1}$. What is the rate (in $mol \ L^{-1} \ min^{-1}$) of the backward reaction at equilibrium?

$A$ chemical reaction $A \rightleftharpoons B$ is said to be in equilibrium when ........

In the chemical reaction ${N_2} + 3{H_2} \rightleftharpoons 2N{H_3}$,at the equilibrium point ...............

If some $He$ gas is added to the equilibrium $PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$ at constant pressure and temperature,the equilibrium constant of the reaction will....

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo