Match the items in Column-$I$ with the items in Column-$II$ correctly.
Column-$I$ Column-$II$
$(1)$ Acceleration is positive $(a)$ Speed of the particle decreases
$(2)$ Acceleration is negative $(b)$ Speed of the particle increases
$(c)$ Speed of the particle keeps changing

  • A
    $1-b, 2-a$
  • B
    $1-a, 2-b$
  • C
    $1-c, 2-a$
  • D
    $1-b, 2-c$

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Similar Questions

Match the following columns.
Column $I$Column $II$
$(A)$ $\frac{dv}{dt}$$(p)$ Acceleration
$(B)$ $\frac{d|v|}{dt}$$(q)$ Magnitude of acceleration
$(C)$ $\frac{dr}{dt}$$(r)$ Velocity
$(D)$ $\left|\frac{dr}{dt}\right|$$(s)$ Magnitude of velocity

Draw the $x-t$ graphs for positive,negative,and zero acceleration.

The relation between the displacement $x$ (in metre) and the time $t$ (in second) of a particle is $t = 2x^2 + 3x$. If the displacement of the particle is $25 \ cm$ from the origin $(x = 0)$, then the acceleration of the particle is:

The position $x$ of a particle varies with time as $x = at^2 - bt^3$,where $a$ and $b$ are constants. The acceleration of the particle will be zero at:

$Assertion$ : Retardation is directly opposite to the velocity.
$Reason$ : Retardation is equal to the time rate of decrease of speed.

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