Calculate the molecular formula of an iron ox | vedclass

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Question

(A) To find the empirical formula,we calculate the mole ratio of the elements:      Element    Mass % / Atomic Mass        $Fe$    $\frac{69.9}{55.85}

Vedclass · Accepted Answer

$Fe_2O_3$

Vedclass · Answer

(A) To find the empirical formula,we calculate the mole ratio of the elements:      Element    Mass % / Atomic Mass        $Fe$    $\frac{69.9}{55.85} \approx 1.25$        $O$    $\frac{30.1}{16.00} \approx 1.88$  Dividing by the smallest value $(1.25)$:$Fe: \frac{1.25}{1.25} = 1$$O: \frac{1.88}{1.25} = 1.5$To get whole numbers,multiply by $2$:$Fe: 1 	imes 2 = 2$$O: 1.5 	imes 2 = 3$Thus,the empirical formula is $Fe_2O_3$.

Calculate the molecular formula of an iron oxide,in which the mass percentages of iron and oxygen are $69.9$ and $30.1$,respectively.

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