(A) The formula for molarity is: $M = \frac{w \times 1000}{m \times V(mL)}$Where:$w = \text{mass of solute in } g$$m = \text{molar mass of solute} = 8

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(A) The formula for molarity is: $M = \frac{w \times 1000}{m \times V(mL)}$Where:$w = \text{mass of solute in } g$$m = \text{molar mass of solute} = 82.0245 \ g \ mol^{-1}$$V = \text{volume of solution} = 500 \ mL$$M = \text{molarity} = 0.375 \ M$Rearranging for $w$:$w = \frac{M \times m \times V(mL)}{1000}$$w = \frac{0.375 \times 82.0245 \times 500}{1000}$$w = 15.3796 \approx 15.38 \ g$

Class 12 Chemistry Solutions Method of expressing concentration of solution

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Calculate the mass of sodium acetate $(CH_3COONa)$ required to make $500 \ mL$ of a $0.375 \ M$ aqueous solution. The molar mass of sodium acetate is $82.0245 \ g \ mol^{-1}$. (in $g$)

A
$15.38$
B
$30.76$
C
$7.69$
D
$41.01$

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Method of expressing concentration of solution

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Calculate the mass of sodium acetate $(CH_3COONa)$ required to make $500 \ mL$ of a $0.375 \ M$ aqueous solution. The molar mass of sodium acetate is $82.0245 \ g \ mol^{-1}$. (in $g$)

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$A$ solution contains $7.8 \ g$ of benzene $(C_6H_6)$ and $46.0 \ g$ of toluene $(C_6H_5CH_3)$. What is the mole fraction of benzene?

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