Calculate the concentration of sugar (C_{12}H | vedclass

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Question

(A) The molar mass of sugar $(C_{12}H_{22}O_{11})$ is $12 	imes 12 + 22 	imes 1 + 11 	imes 16 = 342 \ g \ mol^{-1}$.The number of moles of sugar is

Vedclass · Accepted Answer

$0.0292 \ mol \ L^{-1}$

Vedclass · Answer

(A) The molar mass of sugar $(C_{12}H_{22}O_{11})$ is $12 	imes 12 + 22 	imes 1 + 11 	imes 16 = 342 \ g \ mol^{-1}$.The number of moles of sugar is $n = \frac{	ext{mass}}{	ext{molar mass}} = \frac{20 \ g}{342 \ g \ mol^{-1}} \approx 0.05848 \ mol$.The molarity $(M)$ is defined as $\frac{	ext{moles of solute}}{	ext{volume of solution in } L}$.$M = \frac{0.05848 \ mol}{2 \ L} = 0.02924 \ mol \ L^{-1}$.

Calculate the concentration of sugar $(C_{12}H_{22}O_{11})$ in $mol \ L^{-1}$ if $20 \ g$ of sugar is dissolved in sufficient water to make the final volume $2 \ L$.

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