The $V^{-}A$ group precipitate was dissolved in $HNO_3$ and treated with an excess of $NH_4OH$. It gives a white precipitate because of:

Assign $A, B, C, D$ from the given type of reaction.
$FeCl_3 + NH_3 \text{ (excess)} \longrightarrow Fe(OH)_3 \downarrow$

Sodium carbonate cannot be used in place of ammonium carbonate for the precipitation of the fifth group radicals because

Consider the following reaction scheme: $D(\text{White ppt}) \xleftarrow{Na_2CO_3} A \xrightarrow[\text{in acetic acid}]{K_2CrO_4} B(\text{Yellow ppt})$ and $A \xrightarrow{dil.\ H_2SO_4} C(\text{White ppt})$. If $A$ is a metallic salt,then the white precipitate $D$ must be:

The qualitative distinction of $ZnSO_4$ and $Al_2(SO_4)_3$ can be done by using the reagent

Which ions can be separated using concentrated $NaOH$?